x^2+28=78 eching

$${ x }^{ 2 } +28=78$$

x uchun yechish

$$x=5\sqrt{2}\approx 7,071067812$$

$$x=-5\sqrt{2}\approx -7,071067812$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 28 ni ayirish.

$$x^{2}=78-28$$

50 olish uchun 78 dan 28 ni ayirish.

$$x^{2}=50$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=5\sqrt{2} x=-5\sqrt{2}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 78 ni ayirish.

$$x^{2}+28-78=0$$

-50 olish uchun 28 dan 78 ni ayirish.

$$x^{2}-50=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -50 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-50\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-50\right)}}{2}$$

-4 ni -50 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{200}}{2}$$

200 ning kvadrat ildizini chiqarish.

$$x=\frac{0±10\sqrt{2}}{2}$$

x=\frac{0±10\sqrt{2}}{2} tenglamasini yeching, bunda ± musbat.

$$x=5\sqrt{2}$$

x=\frac{0±10\sqrt{2}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-5\sqrt{2}$$

Tenglama yechildi.

$$x=5\sqrt{2} x=-5\sqrt{2}$$