x^2+25=64 eching

$${ x }^{ 2 } +25=64$$

x uchun yechish

$$x=\sqrt{39}\approx 6,244997998$$

$$x=-\sqrt{39}\approx -6,244997998$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 25 ni ayirish.

$$x^{2}=64-25$$

39 olish uchun 64 dan 25 ni ayirish.

$$x^{2}=39$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{39} x=-\sqrt{39}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 64 ni ayirish.

$$x^{2}+25-64=0$$

-39 olish uchun 25 dan 64 ni ayirish.

$$x^{2}-39=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -39 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-39\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-39\right)}}{2}$$

-4 ni -39 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{156}}{2}$$

156 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{39}}{2}$$

x=\frac{0±2\sqrt{39}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{39}$$

x=\frac{0±2\sqrt{39}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{39}$$

Tenglama yechildi.

$$x=\sqrt{39} x=-\sqrt{39}$$