x^2+16x+6 eching

$${ x }^{ 2 } +16x+6$$

Omil

$$\left(x-\left(-\sqrt{58}-8\right)\right)\left(x-\left(\sqrt{58}-8\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+16x+6=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-16±\sqrt{16^{2}-4\times 6}}{2}$$

16 kvadratini chiqarish.

$$x=\frac{-16±\sqrt{256-4\times 6}}{2}$$

-4 ni 6 marotabaga ko'paytirish.

$$x=\frac{-16±\sqrt{256-24}}{2}$$

256 ni -24 ga qo'shish.

$$x=\frac{-16±\sqrt{232}}{2}$$

232 ning kvadrat ildizini chiqarish.

$$x=\frac{-16±2\sqrt{58}}{2}$$

x=\frac{-16±2\sqrt{58}}{2} tenglamasini yeching, bunda ± musbat. -16 ni 2\sqrt{58} ga qo'shish.

$$x=\frac{2\sqrt{58}-16}{2}$$

-16+2\sqrt{58} ni 2 ga bo'lish.

$$x=\sqrt{58}-8$$

x=\frac{-16±2\sqrt{58}}{2} tenglamasini yeching, bunda ± manfiy. -16 dan 2\sqrt{58} ni ayirish.

$$x=\frac{-2\sqrt{58}-16}{2}$$

-16-2\sqrt{58} ni 2 ga bo'lish.

$$x=-\sqrt{58}-8$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -8+\sqrt{58} ga va x_{2} uchun -8-\sqrt{58} ga bo‘ling.

$$x^{2}+16x+6=\left(x-\left(\sqrt{58}-8\right)\right)\left(x-\left(-\sqrt{58}-8\right)\right)$$

Baholash

$$x^{2}+16x+6$$