x^2+x^2=9/6 eching

$${ x }^{ 2 } + { x }^{ 2 } = \frac{ 9 }{ 6 }$$

x uchun yechish

$$x=\frac{\sqrt{3}}{2}\approx 0,866025404$$

$$x=-\frac{\sqrt{3}}{2}\approx -0,866025404$$

Kvadrat ildizini topish bo'yicha qadamlar

2x^{2} ni olish uchun x^{2} va x^{2} ni birlashtirish.

$$2x^{2}=\frac{9}{6}$$

\frac{9}{6} ulushini 3 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$2x^{2}=\frac{3}{2}$$

Ikki tarafini 2 ga bo‘ling.

$$x^{2}=\frac{\frac{3}{2}}{2}$$

\frac{\frac{3}{2}}{2} ni yagona kasrga aylantiring.

$$x^{2}=\frac{3}{2\times 2}$$

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

$$x^{2}=\frac{3}{4}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\frac{\sqrt{3}}{2} x=-\frac{\sqrt{3}}{2}$$

Kvadrat tenglamalaridan foydalanish qoidalari

2x^{2} ni olish uchun x^{2} va x^{2} ni birlashtirish.

$$2x^{2}=\frac{9}{6}$$

\frac{9}{6} ulushini 3 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$2x^{2}=\frac{3}{2}$$

Ikkala tarafdan \frac{3}{2} ni ayirish.

$$2x^{2}-\frac{3}{2}=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 2 ni a, 0 ni b va -\frac{3}{2} ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\left(-\frac{3}{2}\right)}}{2\times 2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 2\left(-\frac{3}{2}\right)}}{2\times 2}$$

-4 ni 2 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-8\left(-\frac{3}{2}\right)}}{2\times 2}$$

-8 ni -\frac{3}{2} marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{12}}{2\times 2}$$

12 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{3}}{2\times 2}$$

2 ni 2 marotabaga ko'paytirish.

$$x=\frac{0±2\sqrt{3}}{4}$$

x=\frac{0±2\sqrt{3}}{4} tenglamasini yeching, bunda ± musbat.

$$x=\frac{\sqrt{3}}{2}$$

x=\frac{0±2\sqrt{3}}{4} tenglamasini yeching, bunda ± manfiy.

$$x=-\frac{\sqrt{3}}{2}$$

Tenglama yechildi.

$$x=\frac{\sqrt{3}}{2} x=-\frac{\sqrt{3}}{2}$$