x^2+5^2=55 eching

$${ x }^{ 2 } + { 5 }^{ 2 } =55$$

x uchun yechish

$$x=\sqrt{30}\approx 5,477225575$$

$$x=-\sqrt{30}\approx -5,477225575$$

Kvadrat ildizini topish bo'yicha qadamlar

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$x^{2}+25=55$$

Ikkala tarafdan 25 ni ayirish.

$$x^{2}=55-25$$

30 olish uchun 55 dan 25 ni ayirish.

$$x^{2}=30$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{30} x=-\sqrt{30}$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$x^{2}+25=55$$

Ikkala tarafdan 55 ni ayirish.

$$x^{2}+25-55=0$$

-30 olish uchun 25 dan 55 ni ayirish.

$$x^{2}-30=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -30 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-30\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-30\right)}}{2}$$

-4 ni -30 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{120}}{2}$$

120 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{30}}{2}$$

x=\frac{0±2\sqrt{30}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{30}$$

x=\frac{0±2\sqrt{30}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{30}$$

Tenglama yechildi.

$$x=\sqrt{30} x=-\sqrt{30}$$