m uchun yechish
m=1+2i
m=1-2i
Baham ko'rish
Klipbordga nusxa olish
m^{2}-2m+5=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
m=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 5}}{2}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, -2 ni b va 5 ni c bilan almashtiring.
m=\frac{-\left(-2\right)±\sqrt{4-4\times 5}}{2}
-2 kvadratini chiqarish.
m=\frac{-\left(-2\right)±\sqrt{4-20}}{2}
-4 ni 5 marotabaga ko'paytirish.
m=\frac{-\left(-2\right)±\sqrt{-16}}{2}
4 ni -20 ga qo'shish.
m=\frac{-\left(-2\right)±4i}{2}
-16 ning kvadrat ildizini chiqarish.
m=\frac{2±4i}{2}
-2 ning teskarisi 2 ga teng.
m=\frac{2+4i}{2}
m=\frac{2±4i}{2} tenglamasini yeching, bunda ± musbat. 2 ni 4i ga qo'shish.
m=1+2i
2+4i ni 2 ga bo'lish.
m=\frac{2-4i}{2}
m=\frac{2±4i}{2} tenglamasini yeching, bunda ± manfiy. 2 dan 4i ni ayirish.
m=1-2i
2-4i ni 2 ga bo'lish.
m=1+2i m=1-2i
Tenglama yechildi.
m^{2}-2m+5=0
Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.
m^{2}-2m+5-5=-5
Tenglamaning ikkala tarafidan 5 ni ayirish.
m^{2}-2m=-5
O‘zidan 5 ayirilsa 0 qoladi.
m^{2}-2m+1=-5+1
-2 ni bo‘lish, x shartining koeffitsienti, 2 ga -1 olish uchun. Keyin, -1 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
m^{2}-2m+1=-4
-5 ni 1 ga qo'shish.
\left(m-1\right)^{2}=-4
m^{2}-2m+1 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(m-1\right)^{2}}=\sqrt{-4}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
m-1=2i m-1=-2i
Qisqartirish.
m=1+2i m=1-2i
1 ni tenglamaning ikkala tarafiga qo'shish.
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