10^x+2-12=22 eching

$${ 10 }^{ x+2 } -12=22$$

x uchun yechish

$$x=-\log_{10}\left(\frac{50}{17}\right)\approx -0,468521083$$

Logaritm ifodasidan foydalanish qadamlari

Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.

$$10^{x+2}-12=22$$

12 ni tenglamaning ikkala tarafiga qo'shish.

$$10^{x+2}=34$$

Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.

$$\log(10^{x+2})=\log(34)$$

Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.

$$\left(x+2\right)\log(10)=\log(34)$$

Tenglamaning ikkala tarafidan 2 ni ayirish.

$$x=\log(34)-2$$

x uchun yechish (complex solution)

$$x=\frac{2\pi n_{1}i}{\ln(10)}-\log_{10}\left(\frac{50}{17}\right)$$

$$n_{1}\in \mathrm{Z}$$