left(x+5right)^2=-20(y-95) eching

$${ \left(x+5 \right) }^{ 2 } =-20(y-95)$$

y uchun yechish

$$y=-\frac{\left(x+5\right)^{2}}{20}+95$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+5\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+10x+25=-20\left(y-95\right)$$

-20 ga y-95 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{2}+10x+25=-20y+1900$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$-20y+1900=x^{2}+10x+25$$

Ikkala tarafdan 1900 ni ayirish.

$$-20y=x^{2}+10x+25-1900$$

-1875 olish uchun 25 dan 1900 ni ayirish.

$$-20y=x^{2}+10x-1875$$

Ikki tarafini -20 ga bo‘ling.

$$\frac{-20y}{-20}=\frac{x^{2}+10x-1875}{-20}$$

-20 ga bo'lish -20 ga ko'paytirishni bekor qiladi.

$$y=\frac{x^{2}+10x-1875}{-20}$$

x^{2}+10x-1875 ni -20 ga bo'lish.

$$y=-\frac{x^{2}}{20}-\frac{x}{2}+\frac{375}{4}$$

x uchun yechish (complex solution)

$$x=-2\sqrt{475-5y}-5$$

$$x=2\sqrt{475-5y}-5$$

x uchun yechish

$$x=-2\sqrt{475-5y}-5$$

$$x=2\sqrt{475-5y}-5\text{, }y\leq 95$$