left(6x+2right)^2-10=0 eching

$${ \left(6x+2 \right) }^{ 2 } -10=0$$

x uchun yechish

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3}\approx 0,193712943$$

$$x=-\frac{\sqrt{10}}{6}-\frac{1}{3}\approx -0,86037961$$

Kvadrat ildizini topish bo'yicha qadamlar

10 ni tenglamaning ikkala tarafiga qo'shish.

$$\left(6x+2\right)^{2}-10+10=10$$

O‘zidan 10 ayirilsa 0 qoladi.

$$\left(6x+2\right)^{2}=10$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$6x+2=\sqrt{10} 6x+2=-\sqrt{10}$$

Tenglamaning ikkala tarafidan 2 ni ayirish.

$$6x+2-2=\sqrt{10}-2 6x+2-2=-\sqrt{10}-2$$

O‘zidan 2 ayirilsa 0 qoladi.

$$6x=\sqrt{10}-2 6x=-\sqrt{10}-2$$

\sqrt{10} dan 2 ni ayirish.

$$6x=\sqrt{10}-2$$

-\sqrt{10} dan 2 ni ayirish.

$$6x=-\sqrt{10}-2$$

Ikki tarafini 6 ga bo‘ling.

$$\frac{6x}{6}=\frac{\sqrt{10}-2}{6} \frac{6x}{6}=\frac{-\sqrt{10}-2}{6}$$

6 ga bo'lish 6 ga ko'paytirishni bekor qiladi.

$$x=\frac{\sqrt{10}-2}{6} x=\frac{-\sqrt{10}-2}{6}$$

\sqrt{10}-2 ni 6 ga bo'lish.

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3}$$

-\sqrt{10}-2 ni 6 ga bo'lish.

$$x=-\frac{\sqrt{10}}{6}-\frac{1}{3}$$

Tenglama yechildi.

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3} x=-\frac{\sqrt{10}}{6}-\frac{1}{3}$$