left(4-xright)^2=x^2+9 eching

$${ \left(4-x \right) }^{ 2 } = { x }^{ 2 } +9$$

x uchun yechish

$$x=\frac{7}{8}=0,875$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(4-x\right)^{2} kengaytirilishi uchun ishlating.

$$16-8x+x^{2}=x^{2}+9$$

Ikkala tarafdan x^{2} ni ayirish.

$$16-8x+x^{2}-x^{2}=9$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$16-8x=9$$

Ikkala tarafdan 16 ni ayirish.

$$-8x=9-16$$

-7 olish uchun 9 dan 16 ni ayirish.

$$-8x=-7$$

Ikki tarafini -8 ga bo‘ling.

$$x=\frac{-7}{-8}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-7}{-8} kasrini \frac{7}{8} ga soddalashtirish mumkin.

$$x=\frac{7}{8}$$