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9+6\sqrt{7}+\left(\sqrt{7}\right)^{2}-6\sqrt{7}
\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(3+\sqrt{7}\right)^{2} kengaytirilishi uchun ishlating.
9+6\sqrt{7}+7-6\sqrt{7}
\sqrt{7} kvadrati – 7.
16+6\sqrt{7}-6\sqrt{7}
16 olish uchun 9 va 7'ni qo'shing.
16
0 ni olish uchun 6\sqrt{7} va -6\sqrt{7} ni birlashtirish.