{left(7/8right)}^2x+3=2 eching

$${ \left( \frac{ 7 }{ 8 } \right) }^{ 2x+3 } =2$$

x uchun yechish

$$x = -\frac{\log_{\frac{7}{8}} {(\frac{343}{1024})}}{2} \approx -4,095446535$$

Logaritm ifodasidan foydalanish qadamlari

Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.

$$\left(\frac{7}{8}\right)^{2x+3}=2$$

Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.

$$\log(\left(\frac{7}{8}\right)^{2x+3})=\log(2)$$

Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.

$$\left(2x+3\right)\log(\frac{7}{8})=\log(2)$$

Ikki tarafini \log(\frac{7}{8}) ga bo‘ling.

$$2x+3=\frac{\log(2)}{\log(\frac{7}{8})}$$

Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$2x+3=\log_{\frac{7}{8}}\left(2\right)$$

Tenglamaning ikkala tarafidan 3 ni ayirish.

$$2x=\frac{\ln(2)}{\ln(\frac{7}{8})}-3$$

Ikki tarafini 2 ga bo‘ling.

$$x=\frac{\frac{\ln(2)}{\ln(\frac{7}{8})}-3}{2}$$

x uchun yechish (complex solution)

$$x=\frac{\pi n_{1}i}{\ln(\frac{7}{8})}-\frac{\log_{\frac{7}{8}}\left(\frac{343}{1024}\right)}{2}$$

$$n_{1}\in \mathrm{Z}$$