x uchun yechish
\left\{\begin{matrix}x=\frac{\epsilon -R}{z+1}\text{, }&z\neq -1\\x\in \mathrm{R}\text{, }&\epsilon =R\text{ and }z=-1\end{matrix}\right,
R uchun yechish
R=\epsilon -x-xz
Baham ko'rish
Klipbordga nusxa olish
-xz-x=R-\epsilon
Ikkala tarafdan \epsilon ni ayirish.
\left(-z-1\right)x=R-\epsilon
x'ga ega bo'lgan barcha shartlarni birlashtirish.
\frac{\left(-z-1\right)x}{-z-1}=\frac{R-\epsilon }{-z-1}
Ikki tarafini -z-1 ga bo‘ling.
x=\frac{R-\epsilon }{-z-1}
-z-1 ga bo'lish -z-1 ga ko'paytirishni bekor qiladi.
x=-\frac{R-\epsilon }{z+1}
R-\epsilon ni -z-1 ga bo'lish.
R=\epsilon -xz-x
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
Misollar
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699 * 533
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
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Chegaralar
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