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\left(\sqrt{2x+5}\right)^{2}=\left(\sqrt{4x+9}\right)^{2}
Tenglamaning ikkala taraf kvadratini chiqarish.
2x+5=\left(\sqrt{4x+9}\right)^{2}
2 daraja ko‘rsatkichini \sqrt{2x+5} ga hisoblang va 2x+5 ni qiymatni oling.
2x+5=4x+9
2 daraja ko‘rsatkichini \sqrt{4x+9} ga hisoblang va 4x+9 ni qiymatni oling.
2x+5-4x=9
Ikkala tarafdan 4x ni ayirish.
-2x+5=9
-2x ni olish uchun 2x va -4x ni birlashtirish.
-2x=9-5
Ikkala tarafdan 5 ni ayirish.
-2x=4
4 olish uchun 9 dan 5 ni ayirish.
x=\frac{4}{-2}
Ikki tarafini -2 ga bo‘ling.
x=-2
-2 ni olish uchun 4 ni -2 ga bo‘ling.
\sqrt{2\left(-2\right)+5}=\sqrt{4\left(-2\right)+9}
\sqrt{2x+5}=\sqrt{4x+9} tenglamasida x uchun -2 ni almashtiring.
1=1
Qisqartirish. x=-2 tenglamani qoniqtiradi.
x=-2
\sqrt{2x+5}=\sqrt{4x+9} tenglamasi noyob yechimga ega.