sqrt{2}*(sqrt{6}+sqrt{2}) eching

$$\sqrt{ 2 } \times ( \sqrt{ 6 } + \sqrt{ 2 } )$$

Baholash

$$2\left(\sqrt{3}+1\right)\approx 5,464101615$$

Yechim qadamlari

\sqrt{2} ga \sqrt{6}+\sqrt{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\sqrt{2}\sqrt{6}+\left(\sqrt{2}\right)^{2}$$

Faktor: 6=2\times 3. \sqrt{2\times 3} koʻpaytmasining kvadrat ildizini \sqrt{2}\sqrt{3} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing.

$$\sqrt{2}\sqrt{2}\sqrt{3}+\left(\sqrt{2}\right)^{2}$$

2 hosil qilish uchun \sqrt{2} va \sqrt{2} ni ko'paytirish.

$$2\sqrt{3}+\left(\sqrt{2}\right)^{2}$$

\sqrt{2} kvadrati – 2.

$$2\sqrt{3}+2$$