sqrt{2}sqrt{4}+4-2div6 eching

$$\sqrt{ 2 } \sqrt{ 4 } +4-2 \div 6$$

Baholash

$$2\sqrt{2}+\frac{11}{3}\approx 6,495093791$$

Yechim qadamlari

Faktor: 4=2\times 2. \sqrt{2\times 2} koʻpaytmasining kvadrat ildizini \sqrt{2}\sqrt{2} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing.

$$\sqrt{2}\sqrt{2}\sqrt{2}+4-\frac{2}{6}$$

2 hosil qilish uchun \sqrt{2} va \sqrt{2} ni ko'paytirish.

$$2\sqrt{2}+4-\frac{2}{6}$$

\frac{2}{6} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$2\sqrt{2}+4-\frac{1}{3}$$

4 ni \frac{12}{3} kasrga o‘giring.

$$2\sqrt{2}+\frac{12}{3}-\frac{1}{3}$$

\frac{12}{3} va \frac{1}{3} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$2\sqrt{2}+\frac{12-1}{3}$$

11 olish uchun 12 dan 1 ni ayirish.

$$2\sqrt{2}+\frac{11}{3}$$

Omil

$$\frac{6 \sqrt{2} + 11}{3} = 6,495093791412857$$