sqrt[3]{n-1}=sqrt{u-1} eching

$$\sqrt[ 3 ] { n - 1 } = \sqrt { u - 1 }$$

u uchun yechish

$$u=\left(n-1\right)^{\frac{2}{3}}+1$$

$$n\geq 1$$

Ildizli tenglamalarni yechish qadamlari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\sqrt{u-1}=\sqrt[3]{n-1}$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$u-1=\left(n-1\right)^{\frac{2}{3}}$$

1 ni tenglamaning ikkala tarafiga qo'shish.

$$u-1-\left(-1\right)=\left(n-1\right)^{\frac{2}{3}}-\left(-1\right)$$

O‘zidan -1 ayirilsa 0 qoladi.

$$u=\left(n-1\right)^{\frac{2}{3}}-\left(-1\right)$$

\left(n-1\right)^{\frac{2}{3}} dan -1 ni ayirish.

$$u=\left(n-1\right)^{\frac{2}{3}}+1$$

n uchun yechish

$$n=\sqrt{u-1}u-\sqrt{u-1}+1$$

$$u\geq 1$$