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\left(\sqrt{x}-2\right)^{2}=\left(\sqrt{x-56}\right)^{2}
Tenglamaning ikkala taraf kvadratini chiqarish.
\left(\sqrt{x}\right)^{2}-4\sqrt{x}+4=\left(\sqrt{x-56}\right)^{2}
\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(\sqrt{x}-2\right)^{2} kengaytirilishi uchun ishlating.
x-4\sqrt{x}+4=\left(\sqrt{x-56}\right)^{2}
2 daraja ko‘rsatkichini \sqrt{x} ga hisoblang va x ni qiymatni oling.
x-4\sqrt{x}+4=x-56
2 daraja ko‘rsatkichini \sqrt{x-56} ga hisoblang va x-56 ni qiymatni oling.
x-4\sqrt{x}+4-x=-56
Ikkala tarafdan x ni ayirish.
-4\sqrt{x}+4=-56
0 ni olish uchun x va -x ni birlashtirish.
-4\sqrt{x}=-56-4
Ikkala tarafdan 4 ni ayirish.
-4\sqrt{x}=-60
-60 olish uchun -56 dan 4 ni ayirish.
\sqrt{x}=\frac{-60}{-4}
Ikki tarafini -4 ga bo‘ling.
\sqrt{x}=15
15 ni olish uchun -60 ni -4 ga bo‘ling.
x=225
Tenglamaning ikkala taraf kvadratini chiqarish.
\sqrt{225}-2=\sqrt{225-56}
\sqrt{x}-2=\sqrt{x-56} tenglamasida x uchun 225 ni almashtiring.
13=13
Qisqartirish. x=225 tenglamani qoniqtiradi.
x=225
\sqrt{x}-2=\sqrt{x-56} tenglamasi noyob yechimga ega.