sqrt{9+4sqrt{36-2sqrt{6^2+8^2}}}=? eching

$$\sqrt { 9 + 4 \sqrt { 36 - 2 \sqrt { 6 ^ { 2 } + 8 ^ { 2 } } } } = ?$$

Baholash

$$5$$

Yechim qadamlari

2 daraja ko‘rsatkichini 6 ga hisoblang va 36 ni qiymatni oling.

$$\sqrt{9+4\sqrt{36-2\sqrt{36+8^{2}}}}$$

2 daraja ko‘rsatkichini 8 ga hisoblang va 64 ni qiymatni oling.

$$\sqrt{9+4\sqrt{36-2\sqrt{36+64}}}$$

100 olish uchun 36 va 64'ni qo'shing.

$$\sqrt{9+4\sqrt{36-2\sqrt{100}}}$$

100 ning kvadrat ildizini hisoblab, 10 natijaga ega bo‘ling.

$$\sqrt{9+4\sqrt{36-2\times 10}}$$

20 hosil qilish uchun 2 va 10 ni ko'paytirish.

$$\sqrt{9+4\sqrt{36-20}}$$

16 olish uchun 36 dan 20 ni ayirish.

$$\sqrt{9+4\sqrt{16}}$$

16 ning kvadrat ildizini hisoblab, 4 natijaga ega bo‘ling.

$$\sqrt{9+4\times 4}$$

16 hosil qilish uchun 4 va 4 ni ko'paytirish.

$$\sqrt{9+16}$$

25 olish uchun 9 va 16'ni qo'shing.

$$\sqrt{25}$$

25 ning kvadrat ildizini hisoblab, 5 natijaga ega bo‘ling.

$$5$$

Omil

$$5$$