sqrt{8y+4}=sqrt{7y+7} eching

$$\sqrt { 8 y + 4 } = \sqrt { 7 y + 7 }$$

y uchun yechish

$$y=3$$

Yechim qadamlari

Tenglamaning ikkala taraf kvadratini chiqarish.

$$\left(\sqrt{8y+4}\right)^{2}=\left(\sqrt{7y+7}\right)^{2}$$

2 daraja ko‘rsatkichini \sqrt{8y+4} ga hisoblang va 8y+4 ni qiymatni oling.

$$8y+4=\left(\sqrt{7y+7}\right)^{2}$$

2 daraja ko‘rsatkichini \sqrt{7y+7} ga hisoblang va 7y+7 ni qiymatni oling.

$$8y+4=7y+7$$

Ikkala tarafdan 7y ni ayirish.

$$8y+4-7y=7$$

y ni olish uchun 8y va -7y ni birlashtirish.

$$y+4=7$$

Ikkala tarafdan 4 ni ayirish.

$$y=7-4$$

3 olish uchun 7 dan 4 ni ayirish.

$$y=3$$

\sqrt{8y+4}=\sqrt{7y+7} tenglamasida y uchun 3 ni almashtiring.

$$\sqrt{8\times 3+4}=\sqrt{7\times 3+7}$$

Qisqartirish. y=3 tenglamani qoniqtiradi.

$$2\times 7^{\frac{1}{2}}=2\times 7^{\frac{1}{2}}$$

\sqrt{8y+4}=\sqrt{7y+7} tenglamasi noyob yechimga ega.

$$y=3$$