sqrt{60^2+(60sqrt{3})^2-628} eching

$$\sqrt { 60 ^ { 2 } + ( 60 \sqrt { 3 } ) ^ { 2 } - 628 }$$

Baholash

$$2\sqrt{3443}\approx 117,354164817$$

Yechim qadamlari

2 daraja ko‘rsatkichini 60 ga hisoblang va 3600 ni qiymatni oling.

$$\sqrt{3600+\left(60\sqrt{3}\right)^{2}-628}$$

\left(60\sqrt{3}\right)^{2} ni kengaytirish.

$$\sqrt{3600+60^{2}\left(\sqrt{3}\right)^{2}-628}$$

2 daraja ko‘rsatkichini 60 ga hisoblang va 3600 ni qiymatni oling.

$$\sqrt{3600+3600\left(\sqrt{3}\right)^{2}-628}$$

\sqrt{3} kvadrati – 3.

$$\sqrt{3600+3600\times 3-628}$$

10800 hosil qilish uchun 3600 va 3 ni ko'paytirish.

$$\sqrt{3600+10800-628}$$

14400 olish uchun 3600 va 10800'ni qo'shing.

$$\sqrt{14400-628}$$

13772 olish uchun 14400 dan 628 ni ayirish.

$$\sqrt{13772}$$

Faktor: 13772=2^{2}\times 3443. \sqrt{2^{2}\times 3443} koʻpaytmasining kvadrat ildizini \sqrt{2^{2}}\sqrt{3443} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 2^{2} ning kvadrat ildizini chiqarish.

$$2\sqrt{3443}$$