sqrt{36}*(-6)+2^5:(-2)-(-2)+15^2= eching

$$\sqrt { 36 } \cdot ( - 6 ) + 2 ^ { 5 } : ( - 2 ) - ( - 2 ) + 15 ^ { 2 } =$$

Baholash

$$175$$

Yechim qadamlari

36 ning kvadrat ildizini hisoblab, 6 natijaga ega bo‘ling.

$$6\left(-6\right)+\frac{2^{5}}{-2}-\left(-2\right)+15^{2}$$

-36 hosil qilish uchun 6 va -6 ni ko'paytirish.

$$-36+\frac{2^{5}}{-2}-\left(-2\right)+15^{2}$$

5 daraja ko‘rsatkichini 2 ga hisoblang va 32 ni qiymatni oling.

$$-36+\frac{32}{-2}-\left(-2\right)+15^{2}$$

-16 ni olish uchun 32 ni -2 ga bo‘ling.

$$-36-16-\left(-2\right)+15^{2}$$

-52 olish uchun -36 dan 16 ni ayirish.

$$-52-\left(-2\right)+15^{2}$$

-2 ning teskarisi 2 ga teng.

$$-52+2+15^{2}$$

-50 olish uchun -52 va 2'ni qo'shing.

$$-50+15^{2}$$

2 daraja ko‘rsatkichini 15 ga hisoblang va 225 ni qiymatni oling.

$$-50+225$$

175 olish uchun -50 va 225'ni qo'shing.

$$175$$

Omil

$$5^{2}\times 7$$