sqrt{25}+4*2^1+36:(3-2)^4+5-2^2= eching

$$\sqrt { 25 } + 4 \cdot 2 ^ { 1 } + 36 : ( 3 - 2 ) ^ { 4 } + 5 - 2 ^ { 2 } =$$

Baholash

$$50$$

Yechim qadamlari

25 ning kvadrat ildizini hisoblab, 5 natijaga ega bo‘ling.

$$5+4\times 2^{1}+\frac{36}{\left(3-2\right)^{4}}+5-2^{2}$$

1 daraja ko‘rsatkichini 2 ga hisoblang va 2 ni qiymatni oling.

$$5+4\times 2+\frac{36}{\left(3-2\right)^{4}}+5-2^{2}$$

8 hosil qilish uchun 4 va 2 ni ko'paytirish.

$$5+8+\frac{36}{\left(3-2\right)^{4}}+5-2^{2}$$

13 olish uchun 5 va 8'ni qo'shing.

$$13+\frac{36}{\left(3-2\right)^{4}}+5-2^{2}$$

1 olish uchun 3 dan 2 ni ayirish.

$$13+\frac{36}{1^{4}}+5-2^{2}$$

4 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.

$$13+\frac{36}{1}+5-2^{2}$$

Har qanday son birga bo‘linganda, natija o‘zi chiqadi.

$$13+36+5-2^{2}$$

49 olish uchun 13 va 36'ni qo'shing.

$$49+5-2^{2}$$

54 olish uchun 49 va 5'ni qo'shing.

$$54-2^{2}$$

2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.

$$54-4$$

50 olish uchun 54 dan 4 ni ayirish.

$$50$$

Omil

$$2\times 5^{2}$$