sqrt{2x-3}=y eching

$$\sqrt { 2 x - 3 } = y$$

x uchun yechish

$$x=\frac{y^{2}+3}{2}$$

$$y\geq 0$$

Ildizli tenglamalarni yechish qadamlari

Tenglamaning ikkala taraf kvadratini chiqarish.

$$2x-3=y^{2}$$

3 ni tenglamaning ikkala tarafiga qo'shish.

$$2x-3-\left(-3\right)=y^{2}-\left(-3\right)$$

O‘zidan -3 ayirilsa 0 qoladi.

$$2x=y^{2}-\left(-3\right)$$

y^{2} dan -3 ni ayirish.

$$2x=y^{2}+3$$

Ikki tarafini 2 ga bo‘ling.

$$\frac{2x}{2}=\frac{y^{2}+3}{2}$$

2 ga bo'lish 2 ga ko'paytirishni bekor qiladi.

$$x=\frac{y^{2}+3}{2}$$

x uchun yechish (complex solution)

$$x=\frac{y^{2}+3}{2}$$

$$arg(y)<\pi \text{ or }y=0$$

y uchun yechish (complex solution)

$$y=\sqrt{2x-3}$$

y uchun yechish

$$y=\sqrt{2x-3}$$

$$x\geq \frac{3}{2}$$