sqrt{2-x}=x-1 eching

$$\sqrt { 2 - x } = x - 1$$

x uchun yechish

$$x = \frac{\sqrt{5} + 1}{2} \approx 1,618033989$$

Yechim qadamlari

Tenglamaning ikkala taraf kvadratini chiqarish.

$$\left(\sqrt{2-x}\right)^{2}=\left(x-1\right)^{2}$$

2 daraja ko‘rsatkichini \sqrt{2-x} ga hisoblang va 2-x ni qiymatni oling.

$$2-x=\left(x-1\right)^{2}$$

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-1\right)^{2} kengaytirilishi uchun ishlating.

$$2-x=x^{2}-2x+1$$

Ikkala tarafdan x^{2} ni ayirish.

$$2-x-x^{2}=-2x+1$$

2x ni ikki tarafga qo’shing.

$$2-x-x^{2}+2x=1$$

x ni olish uchun -x va 2x ni birlashtirish.

$$2+x-x^{2}=1$$

Ikkala tarafdan 1 ni ayirish.

$$2+x-x^{2}-1=0$$

1 olish uchun 2 dan 1 ni ayirish.

$$1+x-x^{2}=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$-x^{2}+x+1=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -1 ni a, 1 ni b va 1 ni c bilan almashtiring.

$$x=\frac{-1±\sqrt{1^{2}-4\left(-1\right)}}{2\left(-1\right)}$$

1 kvadratini chiqarish.

$$x=\frac{-1±\sqrt{1-4\left(-1\right)}}{2\left(-1\right)}$$

-4 ni -1 marotabaga ko'paytirish.

$$x=\frac{-1±\sqrt{1+4}}{2\left(-1\right)}$$

1 ni 4 ga qo'shish.

$$x=\frac{-1±\sqrt{5}}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{-1±\sqrt{5}}{-2}$$

x=\frac{-1±\sqrt{5}}{-2} tenglamasini yeching, bunda ± musbat. -1 ni \sqrt{5} ga qo'shish.

$$x=\frac{\sqrt{5}-1}{-2}$$

-1+\sqrt{5} ni -2 ga bo'lish.

$$x=\frac{1-\sqrt{5}}{2}$$

x=\frac{-1±\sqrt{5}}{-2} tenglamasini yeching, bunda ± manfiy. -1 dan \sqrt{5} ni ayirish.

$$x=\frac{-\sqrt{5}-1}{-2}$$

-1-\sqrt{5} ni -2 ga bo'lish.

$$x=\frac{\sqrt{5}+1}{2}$$

Tenglama yechildi.

$$x=\frac{1-\sqrt{5}}{2} x=\frac{\sqrt{5}+1}{2}$$

\sqrt{2-x}=x-1 tenglamasida x uchun \frac{1-\sqrt{5}}{2} ni almashtiring.

$$\sqrt{2-\frac{1-\sqrt{5}}{2}}=\frac{1-\sqrt{5}}{2}-1$$

Qisqartirish. x=\frac{1-\sqrt{5}}{2} qiymati bu tenglamani qoniqtirmaydi, chunki oʻng va chap tarafdagi belgilar bir-biriga qarama-qarshi.

$$\frac{1}{2}+\frac{1}{2}\times 5^{\frac{1}{2}}=-\frac{1}{2}-\frac{1}{2}\times 5^{\frac{1}{2}}$$

\sqrt{2-x}=x-1 tenglamasida x uchun \frac{\sqrt{5}+1}{2} ni almashtiring.

$$\sqrt{2-\frac{\sqrt{5}+1}{2}}=\frac{\sqrt{5}+1}{2}-1$$

Qisqartirish. x=\frac{\sqrt{5}+1}{2} tenglamani qoniqtiradi.

$$-\left(\frac{1}{2}-\frac{1}{2}\times 5^{\frac{1}{2}}\right)=\frac{1}{2}\times 5^{\frac{1}{2}}-\frac{1}{2}$$

\sqrt{2-x}=x-1 tenglamasi noyob yechimga ega.

$$x=\frac{\sqrt{5}+1}{2}$$