sqrt{2}x+2(sqrt{2}+2)=sqrt{2} eching

$$\sqrt { 2 } x + 2 ( \sqrt { 2 } + 2 ) = \sqrt { 2 }$$

x uchun yechish

$$x=-2\sqrt{2}-1\approx -3,828427125$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 ga \sqrt{2}+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\sqrt{2}x+2\sqrt{2}+4=\sqrt{2}$$

Ikkala tarafdan 2\sqrt{2} ni ayirish.

$$\sqrt{2}x+4=\sqrt{2}-2\sqrt{2}$$

-\sqrt{2} ni olish uchun \sqrt{2} va -2\sqrt{2} ni birlashtirish.

$$\sqrt{2}x+4=-\sqrt{2}$$

Ikkala tarafdan 4 ni ayirish.

$$\sqrt{2}x=-\sqrt{2}-4$$

Ikki tarafini \sqrt{2} ga bo‘ling.

$$\frac{\sqrt{2}x}{\sqrt{2}}=\frac{-\sqrt{2}-4}{\sqrt{2}}$$

\sqrt{2} ga bo'lish \sqrt{2} ga ko'paytirishni bekor qiladi.

$$x=\frac{-\sqrt{2}-4}{\sqrt{2}}$$

-\sqrt{2}-4 ni \sqrt{2} ga bo'lish.

$$x=-2\sqrt{2}-1$$