sqrt{(3^2-5^2)+(8+5*2-3*5)^2} eching

$$\sqrt { ( 3 ^ { 2 } - 5 ^ { 2 } ) + ( 8 + 5 \times 2 - 3 \times 5 ) ^ { 2 } }$$

Baholash (complex solution)

$$\sqrt{7}i\approx 2,645751311i$$

Yechim qadamlari

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$\sqrt{9-5^{2}+\left(8+5\times 2-3\times 5\right)^{2}}$$

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$\sqrt{9-25+\left(8+5\times 2-3\times 5\right)^{2}}$$

-16 olish uchun 9 dan 25 ni ayirish.

$$\sqrt{-16+\left(8+5\times 2-3\times 5\right)^{2}}$$

10 hosil qilish uchun 5 va 2 ni ko'paytirish.

$$\sqrt{-16+\left(8+10-3\times 5\right)^{2}}$$

18 olish uchun 8 va 10'ni qo'shing.

$$\sqrt{-16+\left(18-3\times 5\right)^{2}}$$

15 hosil qilish uchun 3 va 5 ni ko'paytirish.

$$\sqrt{-16+\left(18-15\right)^{2}}$$

3 olish uchun 18 dan 15 ni ayirish.

$$\sqrt{-16+3^{2}}$$

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$\sqrt{-16+9}$$

-7 olish uchun -16 va 9'ni qo'shing.

$$\sqrt{-7}$$

Faktor: -7=7\left(-1\right). \sqrt{7\left(-1\right)} koʻpaytmasining kvadrat ildizini \sqrt{7}\sqrt{-1} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. Ta’rifi bo‘yicha, -1 ning kvadrat ildizi i ga teng.

$$\sqrt{7}i$$

Baholash

$$\text{Indeterminate}$$

Yechim qadamlari

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$\sqrt{9-5^{2}+\left(8+5\times 2-3\times 5\right)^{2}}$$

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$\sqrt{9-25+\left(8+5\times 2-3\times 5\right)^{2}}$$

-16 olish uchun 9 dan 25 ni ayirish.

$$\sqrt{-16+\left(8+5\times 2-3\times 5\right)^{2}}$$

10 hosil qilish uchun 5 va 2 ni ko'paytirish.

$$\sqrt{-16+\left(8+10-3\times 5\right)^{2}}$$

18 olish uchun 8 va 10'ni qo'shing.

$$\sqrt{-16+\left(18-3\times 5\right)^{2}}$$

15 hosil qilish uchun 3 va 5 ni ko'paytirish.

$$\sqrt{-16+\left(18-15\right)^{2}}$$

3 olish uchun 18 dan 15 ni ayirish.

$$\sqrt{-16+3^{2}}$$

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$\sqrt{-16+9}$$

-7 olish uchun -16 va 9'ni qo'shing.

$$\sqrt{-7}$$

Ashyoviy qism (complex solution)

$$0$$