sqrt{(1+6^2)[(11/3)^2-4*121/36]} eching

$$\sqrt { ( 1 + 6 ^ { 2 } ) [ ( \frac { 11 } { 3 } ) ^ { 2 } - 4 \times \frac { 121 } { 36 } ] }$$

Baholash

$$0$$

Yechim qadamlari

2 daraja ko‘rsatkichini 6 ga hisoblang va 36 ni qiymatni oling.

$$\sqrt{\left(1+36\right)\left(\left(\frac{11}{3}\right)^{2}-4\times \frac{121}{36}\right)}$$

37 olish uchun 1 va 36'ni qo'shing.

$$\sqrt{37\left(\left(\frac{11}{3}\right)^{2}-4\times \frac{121}{36}\right)}$$

2 daraja ko‘rsatkichini \frac{11}{3} ga hisoblang va \frac{121}{9} ni qiymatni oling.

$$\sqrt{37\left(\frac{121}{9}-4\times \frac{121}{36}\right)}$$

4\times \frac{121}{36} ni yagona kasrga aylantiring.

$$\sqrt{37\left(\frac{121}{9}-\frac{4\times 121}{36}\right)}$$

484 hosil qilish uchun 4 va 121 ni ko'paytirish.

$$\sqrt{37\left(\frac{121}{9}-\frac{484}{36}\right)}$$

\frac{484}{36} ulushini 4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\sqrt{37\left(\frac{121}{9}-\frac{121}{9}\right)}$$

0 olish uchun \frac{121}{9} dan \frac{121}{9} ni ayirish.

$$\sqrt{37\times 0}$$

0 hosil qilish uchun 37 va 0 ni ko'paytirish.

$$\sqrt{0}$$

0 ning kvadrat ildizini hisoblab, 0 natijaga ega bo‘ling.

$$0$$

Omil

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