sqrt{(1/4)^2+(1/3)^2}=1/2+1/3 eching

$$\sqrt { ( \frac { 1 } { 4 } ) ^ { 2 } + ( \frac { 1 } { 3 } ) ^ { 2 } } = \frac { 1 } { 2 } + \frac { 1 } { 3 }$$

Tasdiqlamoq

Yechim qadamlari

2 daraja ko‘rsatkichini \frac{1}{4} ga hisoblang va \frac{1}{16} ni qiymatni oling.

$$\sqrt{\frac{1}{16}+\left(\frac{1}{3}\right)^{2}}=\frac{1}{2}+\frac{1}{3}$$

2 daraja ko‘rsatkichini \frac{1}{3} ga hisoblang va \frac{1}{9} ni qiymatni oling.

$$\sqrt{\frac{1}{16}+\frac{1}{9}}=\frac{1}{2}+\frac{1}{3}$$

16 va 9 ning eng kichik umumiy karralisi 144 ga teng. \frac{1}{16} va \frac{1}{9} ni 144 maxraj bilan kasrlarga aylantirib oling.

$$\sqrt{\frac{9}{144}+\frac{16}{144}}=\frac{1}{2}+\frac{1}{3}$$

\frac{9}{144} va \frac{16}{144} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\sqrt{\frac{9+16}{144}}=\frac{1}{2}+\frac{1}{3}$$

25 olish uchun 9 va 16'ni qo'shing.

$$\sqrt{\frac{25}{144}}=\frac{1}{2}+\frac{1}{3}$$

\frac{25}{144} boʻlinmasining kvadrat ildizini \frac{\sqrt{25}}{\sqrt{144}} kvadrat ildizlarining boʻlinmasi sifatida qayta yozing. Surat va maxrajni kvadrat ildizdan chiqaring.

$$\frac{5}{12}=\frac{1}{2}+\frac{1}{3}$$

2 va 3 ning eng kichik umumiy karralisi 6 ga teng. \frac{1}{2} va \frac{1}{3} ni 6 maxraj bilan kasrlarga aylantirib oling.

$$\frac{5}{12}=\frac{3}{6}+\frac{2}{6}$$

\frac{3}{6} va \frac{2}{6} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{5}{12}=\frac{3+2}{6}$$

5 olish uchun 3 va 2'ni qo'shing.

$$\frac{5}{12}=\frac{5}{6}$$

12 va 6 ning eng kichik umumiy karralisi 12 ga teng. \frac{5}{12} va \frac{5}{6} ni 12 maxraj bilan kasrlarga aylantirib oling.

$$\frac{5}{12}=\frac{10}{12}$$

\frac{5}{12} va \frac{10}{12} ni taqqoslang.

$$\text{false}$$