sqrt{[(21/2-1/6+02)*9]-11/4}= eching

$$\sqrt { [ ( 2 \frac { 1 } { 2 } - \frac { 1 } { 6 } + 02 ) \cdot 9 ] - \frac { 11 } { 4 } } =$$

Baholash

$$\frac{\sqrt{73}}{2}\approx 4,272001873$$

Yechim qadamlari

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

$$\sqrt{\left(\frac{4+1}{2}-\frac{1}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

5 olish uchun 4 va 1'ni qo'shing.

$$\sqrt{\left(\frac{5}{2}-\frac{1}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

2 va 6 ning eng kichik umumiy karralisi 6 ga teng. \frac{5}{2} va \frac{1}{6} ni 6 maxraj bilan kasrlarga aylantirib oling.

$$\sqrt{\left(\frac{15}{6}-\frac{1}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

\frac{15}{6} va \frac{1}{6} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\sqrt{\left(\frac{15-1}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

14 olish uchun 15 dan 1 ni ayirish.

$$\sqrt{\left(\frac{14}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

\frac{14}{6} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\sqrt{\left(\frac{7}{3}+0\times 2\right)\times 9-\frac{11}{4}}$$

0 hosil qilish uchun 0 va 2 ni ko'paytirish.

$$\sqrt{\left(\frac{7}{3}+0\right)\times 9-\frac{11}{4}}$$

\frac{7}{3} olish uchun \frac{7}{3} va 0'ni qo'shing.

$$\sqrt{\frac{7}{3}\times 9-\frac{11}{4}}$$

\frac{7}{3}\times 9 ni yagona kasrga aylantiring.

$$\sqrt{\frac{7\times 9}{3}-\frac{11}{4}}$$

63 hosil qilish uchun 7 va 9 ni ko'paytirish.

$$\sqrt{\frac{63}{3}-\frac{11}{4}}$$

21 ni olish uchun 63 ni 3 ga bo‘ling.

$$\sqrt{21-\frac{11}{4}}$$

21 ni \frac{84}{4} kasrga o‘giring.

$$\sqrt{\frac{84}{4}-\frac{11}{4}}$$

\frac{84}{4} va \frac{11}{4} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\sqrt{\frac{84-11}{4}}$$

73 olish uchun 84 dan 11 ni ayirish.

$$\sqrt{\frac{73}{4}}$$

\sqrt{\frac{73}{4}} boʻlinmasining kvadrat ildizini \frac{\sqrt{73}}{\sqrt{4}} kvadrat ildizlarining boʻlinmasi sifatida qayta yozing.

$$\frac{\sqrt{73}}{\sqrt{4}}$$

4 ning kvadrat ildizini hisoblab, 2 natijaga ega bo‘ling.

$$\frac{\sqrt{73}}{2}$$