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x_2 ga nisbatan hosilani topish
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\frac{\mathrm{d}}{\mathrm{d}x_{2}}(\sin(x_{2}))=\left(\lim_{h\to 0}\frac{\sin(x_{2}+h)-\sin(x_{2})}{h}\right)
f\left(x\right) funksiyasi uchun, hosilasi \frac{f\left(x+h\right)-f\left(x\right)}{h} cheklovidir, chunki ana shu cheklov mavjud bo'lsa, h 0'ga o'tadi.
\lim_{h\to 0}\frac{\sin(x_{2}+h)-\sin(x_{2})}{h}
Sinus uchun yig'indi formulasidan foydalanish.
\lim_{h\to 0}\frac{\sin(x_{2})\left(\cos(h)-1\right)+\cos(x_{2})\sin(h)}{h}
\sin(x_{2}) omili.
\left(\lim_{h\to 0}\sin(x_{2})\right)\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\left(\lim_{h\to 0}\cos(x_{2})\right)\left(\lim_{h\to 0}\frac{\sin(h)}{h}\right)
Chegarani qayta yozish.
\sin(x_{2})\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(x_{2})\left(\lim_{h\to 0}\frac{\sin(h)}{h}\right)
Limitlar h dan 0 sifatida hisoblanganda x_{2} ni konstanta sifatida foydalanish.
\sin(x_{2})\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(x_{2})
\lim_{x_{2}\to 0}\frac{\sin(x_{2})}{x_{2}} chegarasi 1 dir.
\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)=\left(\lim_{h\to 0}\frac{\left(\cos(h)-1\right)\left(\cos(h)+1\right)}{h\left(\cos(h)+1\right)}\right)
\lim_{h\to 0}\frac{\cos(h)-1}{h} chegarasini baholash uchun, avval surat va maxrajni \cos(h)+1 ga ko'paytiring.
\lim_{h\to 0}\frac{\left(\cos(h)\right)^{2}-1}{h\left(\cos(h)+1\right)}
\cos(h)+1 ni \cos(h)-1 marotabaga ko'paytirish.
\lim_{h\to 0}-\frac{\left(\sin(h)\right)^{2}}{h\left(\cos(h)+1\right)}
Pifagor ayniyatidan foydalanish.
\left(\lim_{h\to 0}-\frac{\sin(h)}{h}\right)\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)
Chegarani qayta yozish.
-\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)
\lim_{x_{2}\to 0}\frac{\sin(x_{2})}{x_{2}} chegarasi 1 dir.
\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)=0
\frac{\sin(h)}{\cos(h)+1} 0 da davomiy sifatida foydalanish.
\cos(x_{2})
0 qiymatini \sin(x_{2})\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(x_{2}) ifodasiga almashtirish.