sigma_x^2=(-2-0)^2*4/9+(0*0)^2x eching

$$\sigma _ { x } ^ { 2 } = ( - 2 - 0 ) ^ { 2 } \times \frac { 4 } { 9 } + ( 0 \times 0 ) ^ { 2 } x$$

σ_x uchun yechish

$$\sigma _{x}=\frac{4}{3}$$

$$\sigma _{x}=-\frac{4}{3}$$

Kvadrat ildizini topish bo'yicha qadamlar

-2 olish uchun -2 dan 0 ni ayirish.

$$\sigma _{x}^{2}=\left(-2\right)^{2}\times \frac{4}{9}+\left(0\times 0\right)^{2}x$$

2 daraja ko‘rsatkichini -2 ga hisoblang va 4 ni qiymatni oling.

$$\sigma _{x}^{2}=4\times \frac{4}{9}+\left(0\times 0\right)^{2}x$$

\frac{16}{9} hosil qilish uchun 4 va \frac{4}{9} ni ko'paytirish.

$$\sigma _{x}^{2}=\frac{16}{9}+\left(0\times 0\right)^{2}x$$

0 hosil qilish uchun 0 va 0 ni ko'paytirish.

$$\sigma _{x}^{2}=\frac{16}{9}+0^{2}x$$

2 daraja ko‘rsatkichini 0 ga hisoblang va 0 ni qiymatni oling.

$$\sigma _{x}^{2}=\frac{16}{9}+0x$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$\sigma _{x}^{2}=\frac{16}{9}+0$$

\frac{16}{9} olish uchun \frac{16}{9} va 0'ni qo'shing.

$$\sigma _{x}^{2}=\frac{16}{9}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sigma _{x}=\frac{4}{3} \sigma _{x}=-\frac{4}{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

-2 olish uchun -2 dan 0 ni ayirish.

$$\sigma _{x}^{2}=\left(-2\right)^{2}\times \frac{4}{9}+\left(0\times 0\right)^{2}x$$

2 daraja ko‘rsatkichini -2 ga hisoblang va 4 ni qiymatni oling.

$$\sigma _{x}^{2}=4\times \frac{4}{9}+\left(0\times 0\right)^{2}x$$

\frac{16}{9} hosil qilish uchun 4 va \frac{4}{9} ni ko'paytirish.

$$\sigma _{x}^{2}=\frac{16}{9}+\left(0\times 0\right)^{2}x$$

0 hosil qilish uchun 0 va 0 ni ko'paytirish.

$$\sigma _{x}^{2}=\frac{16}{9}+0^{2}x$$

2 daraja ko‘rsatkichini 0 ga hisoblang va 0 ni qiymatni oling.

$$\sigma _{x}^{2}=\frac{16}{9}+0x$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$\sigma _{x}^{2}=\frac{16}{9}+0$$

\frac{16}{9} olish uchun \frac{16}{9} va 0'ni qo'shing.

$$\sigma _{x}^{2}=\frac{16}{9}$$

Ikkala tarafdan \frac{16}{9} ni ayirish.

$$\sigma _{x}^{2}-\frac{16}{9}=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -\frac{16}{9} ni c bilan almashtiring.

$$\sigma _{x}=\frac{0±\sqrt{0^{2}-4\left(-\frac{16}{9}\right)}}{2}$$

0 kvadratini chiqarish.

$$\sigma _{x}=\frac{0±\sqrt{-4\left(-\frac{16}{9}\right)}}{2}$$

-4 ni -\frac{16}{9} marotabaga ko'paytirish.

$$\sigma _{x}=\frac{0±\sqrt{\frac{64}{9}}}{2}$$

\frac{64}{9} ning kvadrat ildizini chiqarish.

$$\sigma _{x}=\frac{0±\frac{8}{3}}{2}$$

\sigma _{x}=\frac{0±\frac{8}{3}}{2} tenglamasini yeching, bunda ± musbat.

$$\sigma _{x}=\frac{4}{3}$$

\sigma _{x}=\frac{0±\frac{8}{3}}{2} tenglamasini yeching, bunda ± manfiy.

$$\sigma _{x}=-\frac{4}{3}$$

Tenglama yechildi.

$$\sigma _{x}=\frac{4}{3} \sigma _{x}=-\frac{4}{3}$$

x uchun yechish (complex solution)

$$x\in \mathrm{C}$$

$$\sigma _{x}=\frac{4}{3}\text{ or }\sigma _{x}=-\frac{4}{3}$$

x uchun yechish

$$x\in \mathrm{R}$$

$$|\sigma _{x}|=\frac{4}{3}$$