quadf(x)=(x^2+25)^3 eching

$$\quad f ( x ) = ( x ^ { 2 } + 25 ) ^ { 3 }$$

Baholash

$$\left(x^{2}+25\right)^{3}$$

Yechim qadamlari

\left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} binom teoremasini \left(x^{2}+25\right)^{3} kengaytirilishi uchun ishlating.

$$\left(x^{2}\right)^{3}+75\left(x^{2}\right)^{2}+1875x^{2}+15625$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$x^{6}+75\left(x^{2}\right)^{2}+1875x^{2}+15625$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$x^{6}+75x^{4}+1875x^{2}+15625$$

Kengaytirish

$$x^{6}+75x^{4}+1875x^{2}+15625$$

Yechim qadamlari

\left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} binom teoremasini \left(x^{2}+25\right)^{3} kengaytirilishi uchun ishlating.

$$\left(x^{2}\right)^{3}+75\left(x^{2}\right)^{2}+1875x^{2}+15625$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$x^{6}+75\left(x^{2}\right)^{2}+1875x^{2}+15625$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$x^{6}+75x^{4}+1875x^{2}+15625$$