pir^2=17 eching

$$\pi r ^ { 2 } = 17$$

r uchun yechish

$$r=\sqrt{\frac{17}{\pi }}\approx 2,326213246$$

$$r=-\sqrt{\frac{17}{\pi }}\approx -2,326213246$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini \pi ga bo‘ling.

$$\frac{\pi r^{2}}{\pi }=\frac{17}{\pi }$$

\pi ga bo'lish \pi ga ko'paytirishni bekor qiladi.

$$r^{2}=\frac{17}{\pi }$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$r=\frac{17}{\sqrt{17\pi }} r=-\frac{17}{\sqrt{17\pi }}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 17 ni ayirish.

$$\pi r^{2}-17=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} \pi ni a, 0 ni b va -17 ni c bilan almashtiring.

$$r=\frac{0±\sqrt{0^{2}-4\pi \left(-17\right)}}{2\pi }$$

0 kvadratini chiqarish.

$$r=\frac{0±\sqrt{-4\pi \left(-17\right)}}{2\pi }$$

-4 ni \pi marotabaga ko'paytirish.

$$r=\frac{0±\sqrt{\left(-4\pi \right)\left(-17\right)}}{2\pi }$$

-4\pi ni -17 marotabaga ko'paytirish.

$$r=\frac{0±\sqrt{68\pi }}{2\pi }$$

68\pi ning kvadrat ildizini chiqarish.

$$r=\frac{0±2\sqrt{17\pi }}{2\pi }$$

r=\frac{0±2\sqrt{17\pi }}{2\pi } tenglamasini yeching, bunda ± musbat.

$$r=\frac{17}{\sqrt{17\pi }}$$

r=\frac{0±2\sqrt{17\pi }}{2\pi } tenglamasini yeching, bunda ± manfiy.

$$r=-\frac{17}{\sqrt{17\pi }}$$

Tenglama yechildi.

$$r=\frac{17}{\sqrt{17\pi }} r=-\frac{17}{\sqrt{17\pi }}$$