pi({left(95/2right)}^2 eching | Microsoft math hal qiluvchi

\pi ( { \left( \frac{ 95 }{ 2 } \right) }^{ 2 }

Baholash

\frac{9025\pi }{4}\approx 7088,218424662

Yechim qadamlari

\pi ( { \left( \frac{ 95 }{ 2 } \right) }^{ 2 }

2 daraja ko‘rsatkichini \frac{95}{2} ga hisoblang va \frac{9025}{4} ni qiymatni oling.

\pi \times \frac{9025}{4}

Viktorina

5xshash muammolar:

\pi ( { \left( \frac{ 95 }{ 2 } \right) }^{ 2 }

Veb-qidiruvdagi o'xshash muammolar

How i could prove this:F(x)=\int_{0}^{\pi/2} \cos^{x}\! \theta \cos(x\theta){\mathrm{d}}\theta= \frac{\pi}{2^{a+1}}, \quad

https://math.stackexchange.com/questions/849826/how-i-could-prove-thisfx-int-0-pi-2-cosx-theta-cosx-theta-m

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Inverse of 2d function involving sine and cosine

https://math.stackexchange.com/q/868337

Let's write (u,v) = \Big( \sin(x-y) \:\: , \:\: \frac{1}{2} \cos(x-y) - \frac{1}{2} \cos(x+y) \Big) As Daniel Fischer noted, x-y=\arcsin u\tag1 because -\pi/2\le x-y\le \pi/2. Furthermore, ...

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https://math.stackexchange.com/questions/325096/find-iint-xyx2-y21-2-mathrm-da

Alternatively, you can consider the region as pairs (x,y) with x\in[0,1] and y\in [\sqrt{1-x^2},1]: \int_{0}^1 \int_{\sqrt{1-x^2}}^1 xy\sqrt{x^2+y^2} dy dx For any particular x, it is easy ...

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https://math.stackexchange.com/questions/648834/estimate-int-0-infty-1-sqrt1x4-mathrmdx

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https://math.stackexchange.com/questions/367643/optimization-and-window-area

OK, I spotted the error: when you wrote the expression (which Anil Baseski repeated) for the perimeter, you used the circumference of a circle written as C = \pi d. However, the "lunette" of the ...

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https://math.stackexchange.com/questions/3057871/factor-polynomials

x^4-23x^2+1=x^4+2x^2+1-25x^2=(x^2-5x+1)(x^2+5x+1). 2x^2-5xy+2y^2-ax-ay-a^2= =2x^2-5xy+2y^2+\frac{1}{4}(x+y)^2-\frac{1}{4}(x+y)^2-a(x+y)-a^2= =\frac{9}{4}(x-y)^2-\left(\frac{1}{2}(x+y)+a\right)^2= ...

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Klipbordga nusxa olish

\pi \times \frac{9025}{4}

2 daraja ko‘rsatkichini \frac{95}{2} ga hisoblang va \frac{9025}{4} ni qiymatni oling.

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