operatorname{h}(x)=x^2+6^x-27/x^2-8x+7 eching

$$\operatorname { h } ( x ) = \frac { x ^ { 2 } + 6 ^ { x } - 27 } { x ^ { 2 } - 8 x + 7 }$$

h uchun yechish

$$h=-\frac{27-6^{x}-x^{2}}{x\left(x-7\right)\left(x-1\right)}$$

$$x\neq 1\text{ and }x\neq 7\text{ and }x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini \left(x-7\right)\left(x-1\right) ga ko'paytirish.

$$hx\left(x-7\right)\left(x-1\right)=x^{2}+6^{x}-27$$

hx ga x-7 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(hx^{2}-7hx\right)\left(x-1\right)=x^{2}+6^{x}-27$$

hx^{2}-7hx ga x-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$hx^{3}-8hx^{2}+7hx=x^{2}+6^{x}-27$$

h'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(x^{3}-8x^{2}+7x\right)h=x^{2}+6^{x}-27$$

Ikki tarafini -8x^{2}+x^{3}+7x ga bo‘ling.

$$\frac{\left(x^{3}-8x^{2}+7x\right)h}{x^{3}-8x^{2}+7x}=\frac{x^{2}+6^{x}-27}{x^{3}-8x^{2}+7x}$$

-8x^{2}+x^{3}+7x ga bo'lish -8x^{2}+x^{3}+7x ga ko'paytirishni bekor qiladi.

$$h=\frac{x^{2}+6^{x}-27}{x^{3}-8x^{2}+7x}$$

x^{2}+6^{x}-27 ni -8x^{2}+x^{3}+7x ga bo'lish.

$$h=\frac{x^{2}+6^{x}-27}{x\left(x-7\right)\left(x-1\right)}$$