{rrr}{3}&{-1}&{2}{1}&{0}&{-1}{-2}&{1}&{4} eching

$$\left( \begin{array} { r r r } { 3 } & { - 1 } & { 2 } \\ { 1 } & { 0 } & { - 1 } \\ { - 2 } & { 1 } & { 4 } \end{array} \right)$$

Determinantni hisoblash

$$7$$

Sarrus qoidasidan foydalanish qadamlari

Diagonal usulidan foydalanib matritsaning aniqlovchisini topish.

$$det(\left(\begin{matrix}3&-1&2\\1&0&-1\\-2&1&4\end{matrix}\right))$$

Birinchi ikki ustunni to'rtinchi va beshinchi ustun sifatida qaytarish uchun asl matritsani kengaytirish.

$$\left(\begin{matrix}3&-1&2&3&-1\\1&0&-1&1&0\\-2&1&4&-2&1\end{matrix}\right)$$

Pastki chap kiritmadan boshlab diagonal kamayish tarafga ko'paytirish ha koʻpaytmalarni qo'shish.

$$-\left(-1\right)\left(-2\right)+2=0$$

Pastki chap kiritmadan boshlab diagonal ko'payish tarafga koʻpaytirish va koʻpaytmalarni qoʻshish.

$$-3+4\left(-1\right)=-7$$

Kamayib boruvchi diagonal koʻpaytmalarning yig'indisidan ko'payib boruvchi diagonal koʻpaytmalar yig'indisini ayirish.

$$-\left(-7\right)$$

Ikkilamchilar bilan kengayishdan foydalanish qadamlari

Kichik a'zolarni kengaytirish usulidan foydalanib matritsaning aniqlovchisini topish (ko'paytiruvchilarni kengaytirish deb ham nomlanadi).

$$det(\left(\begin{matrix}3&-1&2\\1&0&-1\\-2&1&4\end{matrix}\right))$$

Kichik a’zolarga kengaytirish uchun birinchi satrning har bir elementini o‘zining kichik a’zosiga ko‘paytiring, qaysiki ana shu elementga ega bo‘lgan satr va ustunni yo‘q qilish orqali yaratilgan 2\times 2 matritsasining maxraji hisoblanadi, so‘ngra elementning joylashuv belgisiga ko‘paytiring.

$$3det(\left(\begin{matrix}0&-1\\1&4\end{matrix}\right))-\left(-det(\left(\begin{matrix}1&-1\\-2&4\end{matrix}\right))\right)+2det(\left(\begin{matrix}1&0\\-2&1\end{matrix}\right))$$

\left(\begin{matrix}a&b\\c&d\end{matrix}\right) 2\times 2 matritsasi uchun, determinant ad-bc.

$$3\left(-\left(-1\right)\right)-\left(-\left(4-\left(-2\left(-1\right)\right)\right)\right)+2$$

Qisqartirish.

$$3-\left(-2\right)+2$$

Yakuniy natija olish uchun shartlarni qo'shish.

$$7$$

Baholash

$$\left(\begin{matrix}3&-1&2\\1&0&-1\\-2&1&4\end{matrix}\right)$$