{lll}{2}&{5}&{2}{3}&{2}&{1}{4}&{3}&{1} eching

$$\left( \begin{array} { l l l } { 2 } & { 5 } & { 2 } \\ { 3 } & { 2 } & { 1 } \\ { 4 } & { 3 } & { 1 } \end{array} \right)$$

Determinantni hisoblash

$$5$$

Sarrus qoidasidan foydalanish qadamlari

Diagonal usulidan foydalanib matritsaning aniqlovchisini topish.

$$det(\left(\begin{matrix}2&5&2\\3&2&1\\4&3&1\end{matrix}\right))$$

Birinchi ikki ustunni to'rtinchi va beshinchi ustun sifatida qaytarish uchun asl matritsani kengaytirish.

$$\left(\begin{matrix}2&5&2&2&5\\3&2&1&3&2\\4&3&1&4&3\end{matrix}\right)$$

Pastki chap kiritmadan boshlab diagonal kamayish tarafga ko'paytirish ha koʻpaytmalarni qo'shish.

$$2\times 2+5\times 4+2\times 3\times 3=42$$

Pastki chap kiritmadan boshlab diagonal ko'payish tarafga koʻpaytirish va koʻpaytmalarni qoʻshish.

$$4\times 2\times 2+3\times 2+3\times 5=37$$

Kamayib boruvchi diagonal koʻpaytmalarning yig'indisidan ko'payib boruvchi diagonal koʻpaytmalar yig'indisini ayirish.

$$42-37$$

42 dan 37 ni ayirish.

$$5$$

Ikkilamchilar bilan kengayishdan foydalanish qadamlari

Kichik a'zolarni kengaytirish usulidan foydalanib matritsaning aniqlovchisini topish (ko'paytiruvchilarni kengaytirish deb ham nomlanadi).

$$det(\left(\begin{matrix}2&5&2\\3&2&1\\4&3&1\end{matrix}\right))$$

Kichik a’zolarga kengaytirish uchun birinchi satrning har bir elementini o‘zining kichik a’zosiga ko‘paytiring, qaysiki ana shu elementga ega bo‘lgan satr va ustunni yo‘q qilish orqali yaratilgan 2\times 2 matritsasining maxraji hisoblanadi, so‘ngra elementning joylashuv belgisiga ko‘paytiring.

$$2det(\left(\begin{matrix}2&1\\3&1\end{matrix}\right))-5det(\left(\begin{matrix}3&1\\4&1\end{matrix}\right))+2det(\left(\begin{matrix}3&2\\4&3\end{matrix}\right))$$

\left(\begin{matrix}a&b\\c&d\end{matrix}\right) 2\times 2 matritsasi uchun, determinant ad-bc.

$$2\left(2-3\right)-5\left(3-4\right)+2\left(3\times 3-4\times 2\right)$$

Qisqartirish.

$$2\left(-1\right)-5\left(-1\right)+2$$

Yakuniy natija olish uchun shartlarni qo'shish.

$$5$$

Baholash

$$\left(\begin{matrix}2&5&2\\3&2&1\\4&3&1\end{matrix}\right)$$