{lll}{i}&{j}&{k}{1}&{2}&{3}{4}&{5}&{6} eching

Baholash

Viktorina

Complex Number

Veb-qidiruvdagi o'xshash muammolar

https://socratic.org/questions/how-do-you-find-the-determinant-of-0-1-4-3-2-3-8-3-4

https://socratic.org/questions/how-do-you-find-the-determinant-of-4-6-7-3-2-4-1-1-1

https://socratic.org/questions/how-do-you-find-the-value-of-the-determinant-6-3-1-0-3-3-9-0-0

https://socratic.org/questions/how-to-calculate-this-abs-4-4-m-6-m-3-m-3-3-4

https://socratic.org/questions/how-do-you-find-the-determinant-of-8-9-3-3-5-7-1-2-4

https://math.stackexchange.com/questions/2939089/taking-signs-out-of-columns-of-matrix

Baham ko'rish

Klipbordga nusxa olish

det(\left(\begin{matrix}i&j&k\\1&2&3\\4&5&6\end{matrix}\right))

Diagonal usulidan foydalanib matritsaning aniqlovchisini topish.

\left(\begin{matrix}i&j&k&i&j\\1&2&3&1&2\\4&5&6&4&5\end{matrix}\right)

Birinchi ikki ustunni to'rtinchi va beshinchi ustun sifatida qaytarish uchun asl matritsani kengaytirish.

2i\times 6+j\times 3\times 4+k\times 5=12j+5k+12i

Pastki chap kiritmadan boshlab diagonal kamayish tarafga ko'paytirish ha koʻpaytmalarni qo'shish.

4\times 2k+5\times \left(3i\right)+6j=6j+8k+15i

Pastki chap kiritmadan boshlab diagonal ko'payish tarafga koʻpaytirish va koʻpaytmalarni qoʻshish.

12j+5k+12i-\left(6j+8k+15i\right)

Kamayib boruvchi diagonal koʻpaytmalarning yig'indisidan ko'payib boruvchi diagonal koʻpaytmalar yig'indisini ayirish.

6j-3k-3i

12i+12j+5k dan 8k+15i+6j ni ayirish.

det(\left(\begin{matrix}i&j&k\\1&2&3\\4&5&6\end{matrix}\right))

Kichik a'zolarni kengaytirish usulidan foydalanib matritsaning aniqlovchisini topish (ko'paytiruvchilarni kengaytirish deb ham nomlanadi).

idet(\left(\begin{matrix}2&3\\5&6\end{matrix}\right))-jdet(\left(\begin{matrix}1&3\\4&6\end{matrix}\right))+kdet(\left(\begin{matrix}1&2\\4&5\end{matrix}\right))

Kichik a’zolarga kengaytirish uchun birinchi satrning har bir elementini o‘zining kichik a’zosiga ko‘paytiring, qaysiki ana shu elementga ega bo‘lgan satr va ustunni yo‘q qilish orqali yaratilgan 2\times 2 matritsasining maxraji hisoblanadi, so‘ngra elementning joylashuv belgisiga ko‘paytiring.

i\left(2\times 6-5\times 3\right)-j\left(6-4\times 3\right)+k\left(5-4\times 2\right)

\left(\begin{matrix}a&b\\c&d\end{matrix}\right) 2\times 2 matritsasi uchun, determinant ad-bc.

-3i-j\left(-6\right)+k\left(-3\right)

Qisqartirish.

6j-3k-3i

Yakuniy natija olish uchun shartlarni qo'shish.