{lll}{1}&{2}&{4}{8}&{6}&{6}{4}&{3}&{1} eching

$$\left| \begin{array} { l l l } { 1 } & { 2 } & { 4 } \\ { 8 } & { 6 } & { 6 } \\ { 4 } & { 3 } & { 1 } \end{array} \right|$$

Baholash

$$20$$

Sarrus qoidasidan foydalanish qadamlari

Diagonal usulidan foydalanib matritsaning aniqlovchisini topish.

$$det(\left(\begin{matrix}1&2&4\\8&6&6\\4&3&1\end{matrix}\right))$$

Birinchi ikki ustunni to'rtinchi va beshinchi ustun sifatida qaytarish uchun asl matritsani kengaytirish.

$$\left(\begin{matrix}1&2&4&1&2\\8&6&6&8&6\\4&3&1&4&3\end{matrix}\right)$$

Pastki chap kiritmadan boshlab diagonal kamayish tarafga ko'paytirish ha koʻpaytmalarni qo'shish.

$$6+2\times 6\times 4+4\times 8\times 3=150$$

Pastki chap kiritmadan boshlab diagonal ko'payish tarafga koʻpaytirish va koʻpaytmalarni qoʻshish.

$$4\times 6\times 4+3\times 6+8\times 2=130$$

Kamayib boruvchi diagonal koʻpaytmalarning yig'indisidan ko'payib boruvchi diagonal koʻpaytmalar yig'indisini ayirish.

$$150-130$$

150 dan 130 ni ayirish.

$$20$$

Ikkilamchilar bilan kengayishdan foydalanish qadamlari

Kichik a'zolarni kengaytirish usulidan foydalanib matritsaning aniqlovchisini topish (ko'paytiruvchilarni kengaytirish deb ham nomlanadi).

$$det(\left(\begin{matrix}1&2&4\\8&6&6\\4&3&1\end{matrix}\right))$$

Kichik a’zolarga kengaytirish uchun birinchi satrning har bir elementini o‘zining kichik a’zosiga ko‘paytiring, qaysiki ana shu elementga ega bo‘lgan satr va ustunni yo‘q qilish orqali yaratilgan 2\times 2 matritsasining maxraji hisoblanadi, so‘ngra elementning joylashuv belgisiga ko‘paytiring.

$$det(\left(\begin{matrix}6&6\\3&1\end{matrix}\right))-2det(\left(\begin{matrix}8&6\\4&1\end{matrix}\right))+4det(\left(\begin{matrix}8&6\\4&3\end{matrix}\right))$$

\left(\begin{matrix}a&b\\c&d\end{matrix}\right) 2\times 2 matritsasi uchun, determinant ad-bc.

$$6-3\times 6-2\left(8-4\times 6\right)+4\left(8\times 3-4\times 6\right)$$

Qisqartirish.

$$-12-2\left(-16\right)$$

Yakuniy natija olish uchun shartlarni qo'shish.

$$20$$

Omil

$$2^{2}\times 5$$