{lll}{1}&{2}&{1}{2}&{3}&{4}{3}&{4}&{5} eching

$$\left| \begin{array} { l l l } { 1 } & { 2 } & { 1 } \\ { 2 } & { 3 } & { 4 } \\ { 3 } & { 4 } & { 5 } \end{array} \right|$$

Baholash

$$2$$

Sarrus qoidasidan foydalanish qadamlari

Diagonal usulidan foydalanib matritsaning aniqlovchisini topish.

$$det(\left(\begin{matrix}1&2&1\\2&3&4\\3&4&5\end{matrix}\right))$$

Birinchi ikki ustunni to'rtinchi va beshinchi ustun sifatida qaytarish uchun asl matritsani kengaytirish.

$$\left(\begin{matrix}1&2&1&1&2\\2&3&4&2&3\\3&4&5&3&4\end{matrix}\right)$$

Pastki chap kiritmadan boshlab diagonal kamayish tarafga ko'paytirish ha koʻpaytmalarni qo'shish.

$$3\times 5+2\times 4\times 3+2\times 4=47$$

Pastki chap kiritmadan boshlab diagonal ko'payish tarafga koʻpaytirish va koʻpaytmalarni qoʻshish.

$$3\times 3+4\times 4+5\times 2\times 2=45$$

Kamayib boruvchi diagonal koʻpaytmalarning yig'indisidan ko'payib boruvchi diagonal koʻpaytmalar yig'indisini ayirish.

$$47-45$$

47 dan 45 ni ayirish.

$$2$$

Ikkilamchilar bilan kengayishdan foydalanish qadamlari

Kichik a'zolarni kengaytirish usulidan foydalanib matritsaning aniqlovchisini topish (ko'paytiruvchilarni kengaytirish deb ham nomlanadi).

$$det(\left(\begin{matrix}1&2&1\\2&3&4\\3&4&5\end{matrix}\right))$$

Kichik a’zolarga kengaytirish uchun birinchi satrning har bir elementini o‘zining kichik a’zosiga ko‘paytiring, qaysiki ana shu elementga ega bo‘lgan satr va ustunni yo‘q qilish orqali yaratilgan 2\times 2 matritsasining maxraji hisoblanadi, so‘ngra elementning joylashuv belgisiga ko‘paytiring.

$$det(\left(\begin{matrix}3&4\\4&5\end{matrix}\right))-2det(\left(\begin{matrix}2&4\\3&5\end{matrix}\right))+det(\left(\begin{matrix}2&3\\3&4\end{matrix}\right))$$

\left(\begin{matrix}a&b\\c&d\end{matrix}\right) 2\times 2 matritsasi uchun, determinant ad-bc.

$$3\times 5-4\times 4-2\left(2\times 5-3\times 4\right)+2\times 4-3\times 3$$

Qisqartirish.

$$-1-2\left(-2\right)-1$$

Yakuniy natija olish uchun shartlarni qo'shish.

$$2$$

Omil

$$2$$