{ccc}{13}&{11}&{1}{5}&{17}&{0}{1}&{6}&{-2} eching

$$\left| \begin{array} { c c c } { 13 } & { 11 } & { 1 } \\ { 5 } & { 17 } & { 0 } \\ { 1 } & { 6 } & { - 2 } \end{array} \right|$$

Baholash

$$-319$$

Sarrus qoidasidan foydalanish qadamlari

Diagonal usulidan foydalanib matritsaning aniqlovchisini topish.

$$det(\left(\begin{matrix}13&11&1\\5&17&0\\1&6&-2\end{matrix}\right))$$

Birinchi ikki ustunni to'rtinchi va beshinchi ustun sifatida qaytarish uchun asl matritsani kengaytirish.

$$\left(\begin{matrix}13&11&1&13&11\\5&17&0&5&17\\1&6&-2&1&6\end{matrix}\right)$$

Pastki chap kiritmadan boshlab diagonal kamayish tarafga ko'paytirish ha koʻpaytmalarni qo'shish.

$$13\times 17\left(-2\right)+5\times 6=-412$$

Pastki chap kiritmadan boshlab diagonal ko'payish tarafga koʻpaytirish va koʻpaytmalarni qoʻshish.

$$17-2\times 5\times 11=-93$$

Kamayib boruvchi diagonal koʻpaytmalarning yig'indisidan ko'payib boruvchi diagonal koʻpaytmalar yig'indisini ayirish.

$$-412-\left(-93\right)$$

-412 dan -93 ni ayirish.

$$-319$$

Ikkilamchilar bilan kengayishdan foydalanish qadamlari

Kichik a'zolarni kengaytirish usulidan foydalanib matritsaning aniqlovchisini topish (ko'paytiruvchilarni kengaytirish deb ham nomlanadi).

$$det(\left(\begin{matrix}13&11&1\\5&17&0\\1&6&-2\end{matrix}\right))$$

Kichik a’zolarga kengaytirish uchun birinchi satrning har bir elementini o‘zining kichik a’zosiga ko‘paytiring, qaysiki ana shu elementga ega bo‘lgan satr va ustunni yo‘q qilish orqali yaratilgan 2\times 2 matritsasining maxraji hisoblanadi, so‘ngra elementning joylashuv belgisiga ko‘paytiring.

$$13det(\left(\begin{matrix}17&0\\6&-2\end{matrix}\right))-11det(\left(\begin{matrix}5&0\\1&-2\end{matrix}\right))+det(\left(\begin{matrix}5&17\\1&6\end{matrix}\right))$$

2\times 2 matritsasi uchun \left(\begin{matrix}a&b\\c&d\end{matrix}\right), maxraj ad-bc.

$$13\times 17\left(-2\right)-11\times 5\left(-2\right)+5\times 6-17$$

Qisqartirish.

$$13\left(-34\right)-11\left(-10\right)+13$$

Yakuniy natija olish uchun shartlarni qo'shish.

$$-319$$

Omil

$$-319$$