{ccc}{1}&{-1}&{1}{1}&{5}&{-1}{1}&{1}&{6} eching

$$\left| \begin{array} { c c c } { 1 } & { - 1 } & { 1 } \\ { 1 } & { 5 } & { - 1 } \\ { 1 } & { 1 } & { 6 } \end{array} \right|$$

Baholash

$$34$$

Sarrus qoidasidan foydalanish qadamlari

Diagonal usulidan foydalanib matritsaning aniqlovchisini topish.

$$det(\left(\begin{matrix}1&-1&1\\1&5&-1\\1&1&6\end{matrix}\right))$$

Birinchi ikki ustunni to'rtinchi va beshinchi ustun sifatida qaytarish uchun asl matritsani kengaytirish.

$$\left(\begin{matrix}1&-1&1&1&-1\\1&5&-1&1&5\\1&1&6&1&1\end{matrix}\right)$$

Pastki chap kiritmadan boshlab diagonal kamayish tarafga ko'paytirish ha koʻpaytmalarni qo'shish.

$$5\times 6-\left(-1\right)+1=32$$

Pastki chap kiritmadan boshlab diagonal ko'payish tarafga koʻpaytirish va koʻpaytmalarni qoʻshish.

$$5-1+6\left(-1\right)=-2$$

Kamayib boruvchi diagonal koʻpaytmalarning yig'indisidan ko'payib boruvchi diagonal koʻpaytmalar yig'indisini ayirish.

$$32-\left(-2\right)$$

32 dan -2 ni ayirish.

$$34$$

Ikkilamchilar bilan kengayishdan foydalanish qadamlari

Kichik a'zolarni kengaytirish usulidan foydalanib matritsaning aniqlovchisini topish (ko'paytiruvchilarni kengaytirish deb ham nomlanadi).

$$det(\left(\begin{matrix}1&-1&1\\1&5&-1\\1&1&6\end{matrix}\right))$$

Kichik a’zolarga kengaytirish uchun birinchi satrning har bir elementini o‘zining kichik a’zosiga ko‘paytiring, qaysiki ana shu elementga ega bo‘lgan satr va ustunni yo‘q qilish orqali yaratilgan 2\times 2 matritsasining maxraji hisoblanadi, so‘ngra elementning joylashuv belgisiga ko‘paytiring.

$$det(\left(\begin{matrix}5&-1\\1&6\end{matrix}\right))-\left(-det(\left(\begin{matrix}1&-1\\1&6\end{matrix}\right))\right)+det(\left(\begin{matrix}1&5\\1&1\end{matrix}\right))$$

\left(\begin{matrix}a&b\\c&d\end{matrix}\right) 2\times 2 matritsasi uchun, determinant ad-bc.

$$5\times 6-\left(-1\right)-\left(-\left(6-\left(-1\right)\right)\right)+1-5$$

Qisqartirish.

$$31-\left(-7\right)-4$$

Yakuniy natija olish uchun shartlarni qo'shish.

$$34$$

Omil

$$2\times 17$$