\left\{ \begin{array} { l } { y = 3 x } \\ { x + y = 16 } \end{array} \right\}
y, x uchun yechish
x=4
y=12
Grafik
Baham ko'rish
Klipbordga nusxa olish
y-3x=0
Birinchi tenglamani yeching. Ikkala tarafdan 3x ni ayirish.
y-3x=0,y+x=16
Almashtirishdan foydalanib tenglamalar juftligini yechish uchun, avval o'zgaruvchan qiymatlardan biri uchun tenglamani yeching. So'ngra ana shu o'zgaruvchan natijani boshqa tenglama bilan almashtiring.
y-3x=0
Tenglamalardan birini tanlang va teng belgisining chap tomonidagi y ni izolyatsiyalash orqali y ni hisoblang.
y=3x
3x ni tenglamaning ikkala tarafiga qo'shish.
3x+x=16
3x ni y uchun boshqa tenglamada almashtirish, y+x=16.
4x=16
3x ni x ga qo'shish.
x=4
Ikki tarafini 4 ga bo‘ling.
y=3\times 4
4 ni x uchun y=3x da almashtirish. Natija tenglama faqat bitta o'zgaruvchi qiymatga ega bo'lganligi bois siz y ni bevosita yecha olasiz.
y=12
3 ni 4 marotabaga ko'paytirish.
y=12,x=4
Tizim hal qilindi.
y-3x=0
Birinchi tenglamani yeching. Ikkala tarafdan 3x ni ayirish.
y-3x=0,y+x=16
Tenglamalar standart shaklda ko'rsatilsin so'ng tenglamalar tizimini yechish uchun matritsalardan foydalanilsin.
\left(\begin{matrix}1&-3\\1&1\end{matrix}\right)\left(\begin{matrix}y\\x\end{matrix}\right)=\left(\begin{matrix}0\\16\end{matrix}\right)
Tenglamalarni matritsa shaklida yozish.
inverse(\left(\begin{matrix}1&-3\\1&1\end{matrix}\right))\left(\begin{matrix}1&-3\\1&1\end{matrix}\right)\left(\begin{matrix}y\\x\end{matrix}\right)=inverse(\left(\begin{matrix}1&-3\\1&1\end{matrix}\right))\left(\begin{matrix}0\\16\end{matrix}\right)
\left(\begin{matrix}1&-3\\1&1\end{matrix}\right) teskari matritsasi bilan tenglamani chapdan ko‘paytiring.
\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}y\\x\end{matrix}\right)=inverse(\left(\begin{matrix}1&-3\\1&1\end{matrix}\right))\left(\begin{matrix}0\\16\end{matrix}\right)
Matritsaning ko‘paytmasi va teskarisi o‘zaro teng matristsadir.
\left(\begin{matrix}y\\x\end{matrix}\right)=inverse(\left(\begin{matrix}1&-3\\1&1\end{matrix}\right))\left(\begin{matrix}0\\16\end{matrix}\right)
Tenglik belgisining chap tomonida matritsalarni koʻpaytiring.
\left(\begin{matrix}y\\x\end{matrix}\right)=\left(\begin{matrix}\frac{1}{1-\left(-3\right)}&-\frac{-3}{1-\left(-3\right)}\\-\frac{1}{1-\left(-3\right)}&\frac{1}{1-\left(-3\right)}\end{matrix}\right)\left(\begin{matrix}0\\16\end{matrix}\right)
\left(\begin{matrix}a&b\\c&d\end{matrix}\right) 2\times 2 matrix uchun, teskari matritsa \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right), shuning uchun matritsa tenglamasini matritsani ko‘paytirish masalasi sifatida qayta yozish mumkin.
\left(\begin{matrix}y\\x\end{matrix}\right)=\left(\begin{matrix}\frac{1}{4}&\frac{3}{4}\\-\frac{1}{4}&\frac{1}{4}\end{matrix}\right)\left(\begin{matrix}0\\16\end{matrix}\right)
Arifmetik hisobni amalga oshirish.
\left(\begin{matrix}y\\x\end{matrix}\right)=\left(\begin{matrix}\frac{3}{4}\times 16\\\frac{1}{4}\times 16\end{matrix}\right)
Matritsalarni ko'paytirish.
\left(\begin{matrix}y\\x\end{matrix}\right)=\left(\begin{matrix}12\\4\end{matrix}\right)
Arifmetik hisobni amalga oshirish.
y=12,x=4
y va x matritsa elementlarini chiqarib olish.
y-3x=0
Birinchi tenglamani yeching. Ikkala tarafdan 3x ni ayirish.
y-3x=0,y+x=16
Chiqarib tashlash bilan yechim hosil qilish uchun, o'zgartmalarning koeffitsienti ikkala tenglamada bir xil bo'lib o'zgaruvchan qiymat birining boshqasidan ayirilganda, bekor qilishi lozim.
y-y-3x-x=-16
Har bir teng belgisining yon tarafidan o'sxhash shartlarini ayirish orqali y-3x=0 dan y+x=16 ni ayirish.
-3x-x=-16
y ni -y ga qo'shish. y va -y shartlari bekor qilinadi va faqatgina yechimi bor bitta o'zgaruvchan qiymat bilan tenglamani tark etadi.
-4x=-16
-3x ni -x ga qo'shish.
x=4
Ikki tarafini -4 ga bo‘ling.
y+4=16
4 ni x uchun y+x=16 da almashtirish. Natija tenglama faqat bitta o'zgaruvchi qiymatga ega bo'lganligi bois siz y ni bevosita yecha olasiz.
y=12
Tenglamaning ikkala tarafidan 4 ni ayirish.
y=12,x=4
Tizim hal qilindi.
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