∫ (from 6 to 10) of (-x^3/3+14733x)(06x) wrt x eching

$$\int_{ 6 }^{ 10 } (- \frac{ { x }^{ 3 } }{ 3 } +14733x)(06x) d x$$

Baholash

$$0$$

Yechim qadamlari

Ifodalarni qo‘shish yoki ayirish uchun ularni yoyib, maxrajlarini bir xil qiling. 14733x ni \frac{3}{3} marotabaga ko'paytirish.

$$\int _{6}^{10}\left(-\frac{x^{3}}{3}+\frac{3\times 14733x}{3}\right)\times 0\times 6x\mathrm{d}x$$

-\frac{x^{3}}{3} va \frac{3\times 14733x}{3} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\int _{6}^{10}\frac{-x^{3}+3\times 14733x}{3}\times 0\times 6x\mathrm{d}x$$

-x^{3}+3\times 14733x ichidagi ko‘paytirishlarni bajaring.

$$\int _{6}^{10}\frac{-x^{3}+44199x}{3}\times 0\times 6x\mathrm{d}x$$

0 hosil qilish uchun 0 va 6 ni ko'paytirish.

$$\int _{6}^{10}\frac{-x^{3}+44199x}{3}\times 0x\mathrm{d}x$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$\int _{6}^{10}0\mathrm{d}x$$

Avval noaniq integralni baholang.

$$\int 0\mathrm{d}x$$

\int a\mathrm{d}x=ax umumiy integrallar qoidasi jadvalidan foydalanib, 0 integralini toping.

$$0$$

Xos integral bu integral hisoblashning yuqori chegarasida hisoblangan ifodaning boshlangʻich holatidan chiqarib tashlagan holda integral hisoblashning quyi chegarasida hisoblangan ifodaning boshlangʻich holatidir.

$$0+0$$

Qisqartirish.

$$0$$