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\int 12x^{2}\mathrm{d}x+\int 162x\mathrm{d}x+\int 623\mathrm{d}x
Integrate the sum term by term.
12\int x^{2}\mathrm{d}x+162\int x\mathrm{d}x+\int 623\mathrm{d}x
Factor out the constant in each of the terms.
4x^{3}+162\int x\mathrm{d}x+\int 623\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. 12 ni \frac{x^{3}}{3} marotabaga ko'paytirish.
4x^{3}+81x^{2}+\int 623\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. 162 ni \frac{x^{2}}{2} marotabaga ko'paytirish.
4x^{3}+81x^{2}+623x
Find the integral of 623 using the table of common integrals rule \int a\mathrm{d}x=ax.
4x^{3}+81x^{2}+623x+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.