Baholash
10\left(\sqrt{5}-\sqrt{2}\right)\approx 8,218544151
Baham ko'rish
Klipbordga nusxa olish
\int \frac{5}{\sqrt{x}}\mathrm{d}x
Evaluate the indefinite integral first.
5\int \frac{1}{\sqrt{x}}\mathrm{d}x
Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
10\sqrt{x}
\frac{1}{\sqrt{x}} ni x^{-\frac{1}{2}} sifatida qaytadan yozish. Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{-\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{1}{2}}}{\frac{1}{2}}. Simplify and convert from exponential to radical form.
10\times 5^{\frac{1}{2}}-10\times 2^{\frac{1}{2}}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
10\sqrt{5}-10\sqrt{2}
Qisqartirish.
Misollar
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