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\int 1-\frac{x}{2}\mathrm{d}x
Evaluate the indefinite integral first.
\int 1\mathrm{d}x+\int -\frac{x}{2}\mathrm{d}x
Integrate the sum term by term.
\int 1\mathrm{d}x-\frac{\int x\mathrm{d}x}{2}
Factor out the constant in each of the terms.
x-\frac{\int x\mathrm{d}x}{2}
Find the integral of 1 using the table of common integrals rule \int a\mathrm{d}x=ax.
x-\frac{x^{2}}{4}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. -\frac{1}{2} ni \frac{x^{2}}{2} marotabaga ko'paytirish.
3-\frac{3^{2}}{4}-\left(2-\frac{2^{2}}{4}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
-\frac{1}{4}
Qisqartirish.