∫ (from 0 to 1) of x^2+x+1 wrt x eching

$$\int _ { 0 } ^ { 1 } x ^ { 2 } + x + 1 d x$$

Baholash

$$\frac{11}{6}\approx 1,833333333$$

Yechim qadamlari

Avval noaniq integralni baholang.

$$\int x^{2}+x+1\mathrm{d}x$$

Summani muddatma-muddat integratsiya qiling.

$$\int x^{2}\mathrm{d}x+\int x\mathrm{d}x+\int 1\mathrm{d}x$$

k\neq -1 uchun integral \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} boʻlgani uchun, \int x^{2}\mathrm{d}x integralni \frac{x^{3}}{3} bilan almashtiring.

$$\frac{x^{3}}{3}+\int x\mathrm{d}x+\int 1\mathrm{d}x$$

k\neq -1 uchun integral \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} boʻlgani uchun, \int x\mathrm{d}x integralni \frac{x^{2}}{2} bilan almashtiring.

$$\frac{x^{3}}{3}+\frac{x^{2}}{2}+\int 1\mathrm{d}x$$

\int a\mathrm{d}x=ax umumiy integrallar qoidasi jadvalidan foydalanib, 1 integralini toping.

$$\frac{x^{3}}{3}+\frac{x^{2}}{2}+x$$

Xos integral bu integral hisoblashning yuqori chegarasida hisoblangan ifodaning boshlangʻich holatidan chiqarib tashlagan holda integral hisoblashning quyi chegarasida hisoblangan ifodaning boshlangʻich holatidir.

$$\frac{1^{3}}{3}+\frac{1^{2}}{2}+1-\left(\frac{0^{3}}{3}+\frac{0^{2}}{2}+0\right)$$

Qisqartirish.

$$\frac{11}{6}$$