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\int x^{2}+2x+1\mathrm{d}x
Avval noaniq integralni baholang.
\int x^{2}\mathrm{d}x+\int 2x\mathrm{d}x+\int 1\mathrm{d}x
Summani muddatma-muddat integratsiya qiling.
\int x^{2}\mathrm{d}x+2\int x\mathrm{d}x+\int 1\mathrm{d}x
Har bir shartda konstantani qavsdan tashqariga oling.
\frac{x^{3}}{3}+2\int x\mathrm{d}x+\int 1\mathrm{d}x
k\neq -1 uchun integral \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} boʻlgani uchun, \int x^{2}\mathrm{d}x integralni \frac{x^{3}}{3} bilan almashtiring.
\frac{x^{3}}{3}+x^{2}+\int 1\mathrm{d}x
k\neq -1 uchun integral \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} boʻlgani uchun, \int x\mathrm{d}x integralni \frac{x^{2}}{2} bilan almashtiring. 2 ni \frac{x^{2}}{2} marotabaga ko'paytirish.
\frac{x^{3}}{3}+x^{2}+x
\int a\mathrm{d}x=ax umumiy integrallar qoidasi jadvalidan foydalanib, 1 integralini toping.
\frac{1}{3}\left(3-\left(-2\right)^{2}\right)^{3}+\left(3-\left(-2\right)^{2}\right)^{2}+3-\left(-2\right)^{2}-\left(\frac{\left(-1\right)^{3}}{3}+\left(-1\right)^{2}-1\right)
Xos integral bu integral hisoblashning yuqori chegarasida hisoblangan ifodaning boshlangʻich holatidan chiqarib tashlagan holda integral hisoblashning quyi chegarasida hisoblangan ifodaning boshlangʻich holatidir.
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